For example we will look for the day in April the 20th year of 1987. Do we will look for it by opening the calendar of 1988?
It is of course is odd matter, because who have the calendar of 1987. But this matter solvable by using mathematics science.
1. 20th April 1987 located in the year not leap year.
2. Sum many days in before month April, (Jan + Feb + March + Apr = 31 + 28 + 31 + 20 = 110).
3. Determine result from: (1987 - 1) : 4 = 496,5 or 496 remains of 5 (disregarding the rest that is 496).
4. Count: (1987 + 110 + 496) : 7 = 370, 4 or 370 remains 4. Rest of number of 4 is searched for name of day.
5. Friday = 0 Saturday = 1 Sunday = 2 Monday = 3 Tuesday = 4 Wednesday = 5 Thursday = 6
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